Thanks again. I see that the factor m(r) in the denominator of the angular momentum is consistent with the definition of the lagrangian, i.e. L = gamma m r squared phi dot / m(r) — (1)

and this gives conservation of angular momentum in your numerical calculations. So this should be used. However, the lagrangian

Lagrangian = – m c squared gamma + mMg / r

does not give the correct p. This is why I weighted the lagrangian as in Eq. (57) of UFT415.

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