416(1): Summary of the New Cosmology

Thanks again. I see that the factor m(r) in the denominator of the angular momentum is consistent with the definition of the lagrangian, i.e. L = gamma m r squared phi dot / m(r) — (1)
and this gives conservation of angular momentum in your numerical calculations. So this should be used. However, the lagrangian
Lagrangian = – m c squared gamma + mMg / r

does not give the correct p. This is why I weighted the lagrangian as in Eq. (57) of UFT415.

%d bloggers like this: