380(2): Combined Gravitation and Electromagnetism, Biefeld Brown

I agree that Eq. (14) gives the Biefeld Brown effect even in the absence of a spin connection, so it is easy to explain and engineer. The spin connection for any gravitational experiment can be found by using the same methods as in UFT311, by fitting the experimental data. However, as these notes progress, methods emerge for finding the spin connection and Q vectors ab initio. I agree about Eqs. (33) and (34) but in later notes more field equations are used in order to find the scalar components. Also, the methods of the Eckardt / Lindstrom papers can also be used. The overall idea is to find all the spin connection and Q vector components in general, for any problem or application.

To: EMyrone@aol.com
Sent: 25/06/2017 14:49:44 GMT Daylight Time
Subj: Re: 380(2): Combined Gravitation and Electromagnetism, Biefeld Brown

Eq.(14) gives an interesting relation between an electric charge density and a gravitational potential. Eq. (13) is certainly not interesting because the ratio of gravitational to electric propoerties of matter is of order 10 power -21. However by (14) this may look different. It depends on the ratio e/(m*eps0) which is 1.99 * 10^22 in SI units for an electron. The gravitational potential at the earth surface is

Phi(R_E) = -M*G/R_E = -6.26 * 10^7 N m/kg .

This should give strong effects even if bold omega is omitted (because nobody knows this value). However the Biefeld-Brown effect is reported only for non-homogeneous capacitors while this caculation would also hold for linear capacitors…
“Choosing a spin cooection” is a very hypothetical method in my opinion. Nobody knows how to do this because a spin connection is not a dirctly measurable quantity, similar as the probablitly amplitude in quantum mechanics.
Eqs. (33,34) are scalar equations so not 3 variables can be determined from each of them. The computation scheme seems to have to be reworked. What about our earlier findings that the fields E,B (or g,Omega respectively) can be expressed by the potentials alone if there is no unsteady change in the potentials (Papers 293-295)?

Horst

Am 21.06.2017 um 13:40 schrieb EMyrone:

This note gives a scheme of computation on page 7 by which the problem can be solved completely and in general. There are enough equations to find all the unknowns, given of course the skilful use of the computer by co author Horst Eckardt. The Biefeld Brown effect is explained straightforwardly by Eq. (14), which shows that an electric charge density can affect the gravitational scalar potential and therefore can affect g. I did a lit search on the Biefeld Brown effect, it has recently been studied by the U. S. Army Research Laboratory. This report can be found by googling Biefeld Brown effect”, site four. There are various configuration which can all be explained by Eq. (14) – asymmetric electrodes and so on. In the inverse r limit the total potential energy is given by Eq. (19). This gives the planar orbital equations on page 4 of the Note. These can be solved numerically to give some very interesting orbits using the methods of UFT378. The lagrangian in this limit is Eq. (29) and the hamiltonian is Eq. (30). These describe the orbit of a mass m and charge e1 around a mass M and charge e2. If Sommerfeld quantization is applied this method gives the Sommerfeld atom. Otherwise in the classical limit it desribes the orbit of one charge with mass around another. The equations are given in a plane but can easily be extended to three dimensions. Eqs. (31) to (34), solved simultaneously and numerically with Eqs. ((37) and (39), the antisymmetry conditions, are six equations in six unknowns for gravitation and six equations in six unknowns for electromagnetism. These equations give the spin connections and vector potentials in general (three Cartesian components each).


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