Thanks for going through this note. I decided to adopt the new and simpler method of Note 379(5), in which the b index is removed first, to give Eq. (13), and in which the a index is removed by multiplying throughout by the unit vector – e sub a. This gives Eq. (14) of that note. The fields E and g , and the antisymmetry laws, are then the same exactly as in the Engineering Model. The factor two and sign change IN UFT318 come from a different and now obsolete method of removing the a and b indices, and the right signs are those given in Eq. (1) of Note 379(6). This new method produces exact consistency with the Engineering Model. Eq. (41) of Note 379(5) is the same exactly as on page 45 of the Engineering Model (UFT303), and Eq. (42) of Note 379(5) is the same exactly as on page 16 of the Engineering Model.

To: EMyrone@aol.com

Sent: 18/06/2017 20:47:05 GMT Daylight Time

Subj: Re: 379(6): Aharonov Bohm Condition for Zero Gravitation

Concerning note 379(6), could you please explain how eq.(1) can be derived from the antisymmetry condition (30/31) of paper 318? Besides the factor of 2, there is a sign change in the spin connection terms, when inserting eq. (30/31) of paper 318 ito eq. (28) of paper 318 or the corresponding equation for bold g. I guess that eq.(1) of the note contains a sign typo.

Horst

Am 10.06.2017 um 13:43 schrieb EMyrone:

This note deals with the Aharanov Bohm conditions for zero gravitation, Eqs. (4) and (5), and in covariant format, Eq. (15). These equations can be applied to explain any observed counter gravitational effect.

### Like this:

Like Loading...

*Related*

This entry was posted on June 19, 2017 at 8:00 am and is filed under asott2. You can follow any responses to this entry through the RSS 2.0 feed.
Both comments and pings are currently closed.