Yes exactly so. The quantity H0 – H is a constant of motion.

To: EMyrone@aol.com

Sent: 21/03/2017 13:35:57 GMT Standard Time

Subj: Re: 373(6): The Most Fundamental Relativistic Orbit

Question: is H the Newtonian Hamiltonian and H0 that of the relativistic theory minus mc^2 ?

We have to take H0 then as an additional free parameter, close to H.

Horst

Am 21.03.2017 um 11:49 schrieb EMyrone:

This is given by Eqs. (4) and (5), which can be solved by computer algebra to give the relativistic orbital differential function (dr/dphi) squared. In the non relativistic limit it reduces to Eq. (8). The all important advance made by computational solution of the relevant Euler Lagrange equations is that this differential orbital function is known now to be that of a precessing ellipse. So this ties up the solution and I will proceed to writing up Sections 1 and 2 of UFT373.

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