Yes it exists as in the attached, calculated by Wolfram integrator. Google keywords “Wolfram integrator” , first site. This is quite a simple result, so things look good. It is

Integral = – 2a inverse tanh (( b exp (x / a) + 1) power half)

In a message dated 30/09/2012 14:17:06 GMT Daylight Time, writes:

ok, but we have to integrate

sqrt(V_WS + E) dx

with V_WS = 1 / (1 +exp(ax + b))

does this integral exist?

Horst

Am 30.09.2012 15:12, schrieb EMyrone

The Wolfram integrator using Mathematica gives:

integral dx / (1 + b exp(x)) = x – a loge sub e ( b exp (x / a) + 1)

so it is analytical. Here

b = – R sub 0 / a

a229thpapernotes7.pdf

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